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Answer by Soudipta Dutta for drawing balls from an urn (conditional probability)

The answer is the Probability that the first ball is red and the second ball is black, divided by the Probability that the second ballis black.$\frac{P(\text{First Ball is RED AND Second Ball is BLACK)...

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Answer by Graham Kemp for drawing balls from an urn (conditional probability)

Randomly select an urn, draw a ball without replacement, then again randomly select an urn and draw a second ball. Let $D_n$ be the colour of the $n^{th}$ draw, and $U_n$ be the urn from which it is...

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drawing balls from an urn (conditional probability)

Urn A contains 4 white balls and 2 red balls. Urn B contains 3 red balls and 3 black balls. An urn is randomly selected, and then a ball inside of that urn is removed. We then repeat the process of...

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